QT C++ code samples

Grotius wrote: @Tommy,
I have one job that was at high court 2 times this year. It costed me over 7500 dollars.
It is my ex. She blackmailed me several times.
.

I think you got off cheaply. I think my legal fees were closer to $12k. Don't remind me

Yes one day I will get to Europe. My son is already there in Amsterdam working for Tesla. This year I am going to see suppliers in China so you and Tommy will have to wait your turn!

Waiting patiently.
The nice thing is a new hotel is opened some 300 meters from my house, the bad thing is i may have to move in a year or two , near city center, again.

Everyone thanks for your reply !!!

Rod,
Yes one day I will get to Europe. My son is already there in Amsterdam working for Tesla.
Oke nice.. I will wait for you. You are welcome !! I can take you trough the country and show you nice places, driving in style

Tom,
The nice thing is a new hotel is opened some 300 meters from my house
I come and visit you one day. Planning to buy a camper, then it's easy to track trough Europe.

Phill,
I think I will wait till then...
What you have done so far looks great.
Thank you Phill. You have done a very nice plasma application. Everyone is happy with your work !!

Project update.

Today i added the last item's to the contour recognize class. And did also made a basic plasma gcode output.

DxfDecoder gui :


Axis gui :


Okey so far it works.

It has travelheight, cutspeed, m3 and m5.
The m3 and m5 line can be modified to probe sequence's in the settings folder.

Have fun !!!

To download this release : we.tl/t-ZH9L26wVuB

I have a little todo list for this weekend :
- Integrate G40, G41, G42... tool offsets.

Hi,

Today i was programming a little for finding midpoint's for a single line with a math formula.
This for 2 reason's. One it can make arrow's for line direction, and 2, it has the tangential A axis value.

The formula i use, can also be negative, does not matter now :
midpoint x = (x0 + x1) / 2
midpoint y = (y0 + y1) / 2

A formula like this one :


I spotted something i have never seen before.... A unexpected mathematical issue..



My idea was to define a midpoint, that is working okey. It's the blue cross in the middle of the lines.
Then i wanted to find the second midpoint. (seen from the line start point x,y and founded midpoint x,y) Seems easy.
But the math seems to go to zero. Totally weird..

The start x,y and midpoint x,y can make a new second midpoint x,y on the same line.
Here the formula goes unexpected to zero ? :blush:

I have multiplied the phenomenon by a 100 times to see more of the result.
For me it's a unexpected mathematical result i can not define. :whistle:

The program code is attached. Nothing special.

Sparkyyyyyyy !!!

Tommy,

position line start :
x1 = 0
y1 = 0
position line end :
x2 = 100
y2 = 200

calculate midpoint of line
midpoint_x = (x1 + x2) / 2 => 0+100/2
midpoint_y= (y1 + y2) / 2 => 0+200/2

result x,y : 50,100

Okey now we calculate new midpoint, seen from start 0,0 :

position line start :
x1 = 0
y1 = 0
position line end :
x2 = 50
y2 = 100

calculate midpoint of line
midpoint_x = (x1 + x2) / 2 => 0+50/2
midpoint_y= (y1 + y2) / 2 => 0+100/2

Okey this looks good :
result x,y : 25,50